Raj
Solve below question:
2021-10-10 09:54:27
∠BOC = 360° - (∠AOB + ∠AOC) [Sum of all angles at a point = 360°]
⇒ ∠BOC = 360° - (90° + 110°)
⇒ ∠BOC = 360° - 200°
⇒ ∠BOC = 160°
We know that ∠BOC = 2 × ∠BAC
⇒ ∠BAC = (1/2) × ∠BOC
⇒ ∠BAC = (1/2) × 160°
⇒ ∠BAC = 80°
2021-10-10 09:54:27
Prashant
∠BOC = 360° - (∠AOB + ∠AOC) [Sum of all angles at a point = 360°]
⇒ ∠BOC = 360° - (90° + 110°)
⇒ ∠BOC = 360° - 200°
⇒ ∠BOC = 160°
We know that ∠BOC = 2 × ∠BAC
⇒ ∠BAC = (1/2) × ∠BOC
⇒ ∠BAC = (1/2) × 160°
⇒ ∠BAC = 80°