Satlok Gupta
118. Question# grade9, geometry, area, triangle, equilateral, midpoint
2021-10-10 09:53:25
In triangle ABD,
∠ABD + ∠BAD + ∠ADB = 180°[Sum of angles of triangle]
⇒ 35°+ 90° + ∠ADB = 180°
⇒ ∠ADB = 55°
∴ ∠ACB = ∠ADB = 55°[Angles in the same segment of a circle]
2021-10-10 09:53:25
Prashant
Answer
In triangle ABD,
∠ABD + ∠BAD + ∠ADB = 180°[Sum of angles of triangle]
⇒ 35°+ 90° + ∠ADB = 180°
⇒ ∠ADB = 55°
∴ ∠ACB = ∠ADB = 55°[Angles in the same segment of a circle]